If x = loga (bc),y = log b (ca) and z = log c (ab) , then which of the following equation is equal to 1 ?
![Best Answer] 1/(1 + loga bc) + (1 + logb ca) + (1 + logc ab)(1) 0(2) 1(3) abc(4) 1/abc - Brainly.in Best Answer] 1/(1 + loga bc) + (1 + logb ca) + (1 + logc ab)(1) 0(2) 1(3) abc(4) 1/abc - Brainly.in](https://hi-static.z-dn.net/files/d60/ba46ff4484b900dc2203f9fddbee607f.jpg)
Best Answer] 1/(1 + loga bc) + (1 + logb ca) + (1 + logc ab)(1) 0(2) 1(3) abc(4) 1/abc - Brainly.in
If a, b, c are positive real numbers such that loga/(b - c) = logb/(c - a) = logc/(a - b), - Sarthaks eConnect | Largest Online Education Community
If x = 1 + loga bc, y = 1 + logb ca, z = 1 + logc ab, then prove that xy + yz + zx = xyz. - Sarthaks eConnect | Largest Online Education Community
![If x = loga (bc),y = log b (ca) and z = log c (ab) , then which of the following equation is equal to 1 ? If x = loga (bc),y = log b (ca) and z = log c (ab) , then which of the following equation is equal to 1 ?](https://dwes9vv9u0550.cloudfront.net/images/4390391/d920eeec-66eb-4af5-8dd7-b21e4255f3dc.jpg)